\(\frac{1}{2}:2x=-\frac{1}{3}\)
\(2x=\frac{1}{2}:\frac{-1}{3}\)
\(2x=\frac{1}{2}\cdot-3\)
\(2x=-\frac{3}{2}\)
\(x=-\frac{3}{2}:2\)
\(x=-\frac{3}{4}\)
Vậy x = \(-\frac{3}{4}\)
1. Tìm x,biết
a,x^2-2x-3=0
b,2x^2+3=-5x
c,2(x-3)(x+1)=(2x+1)(x-3)-12
d,(2x-1)^2+(2-x)(2x-1)=0
e,-x^2+5x=6
g,(x+3)^2>6x+13
h,(x-3)^2<x^2-5x+1
Please,help me !
5) (x– 5)(x – 1)= (x – 1)(x – 2)
6) 6(х - 3)(х — 4) - 6х(х — 2) = 4
7)-(x + 3)(x – 4) + (x + 1)(x – 1) = 10
8) (2x – 1)(x – 2) – (x + 3)(2x – 7) =3
9) (х - 5)(4 — х) — (х — 1)(х + 3) = -2x^2
10 (4x + 1)(x – 3) - (x- 7)(4x – 1)=15
11) (x + 1)(x² – x + 1) – x(x² – 3) = 4
12) (x – 3)(x² + 3x+9)+ x(5 – x²?) = 6x
13) (3x – 5)(x + 1)– (3x – 1)(x+ 1)=x - 4
14) 5(x – 3)(x – 7)– (5x+ 1)(x – 2)= 8
a) |4-x|+2x=3
b) |x+1|+|x+2|+|x+3|=4x
c) |2x-1|=2
d) |3-2x|+|4y+5|=0
e)x^2+|x-1|=x^2+2
Tìm GTNN:
a)(x-2)^2; b)(2x+1)^2-1; x)(2x+1)^4-3; d)(x-1)^2-(y-1)^2+3; e)/x-3/+y^2-10
HELP ME
tìm đa thức M biết
a,M-(1/2x^2y-5xy^2+x^3-y^3)=3/4xy^2-2x^2y+2y^3-1/3x^2
x.(x+1).(x+6)-x^3=5x
2.(3x-1).(2x+5)-6(2x-1).(x+2)=1
(3x-1).(2x+7)-(x+1).(6x-5)=(x+2)-(x-5)
Tìm x biết :
√2x-3/3x+1=2/3
√x=√2x-1 (x >= 1/2)
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
a) |x-3|=|4-x|
b) |2x-1|+5=5
c) |x-1|(-1/2)^3=(-1 /2)^5
d) 3x-|2x+1|=2
e) |x|+|-x|=3-x
1. Cho hàm số: f(x)=-3|x|+1
A) tính f(0); f(2); f(-2); f(-1/2)
B) tìm x để f(x)=-3
2. Tìm điều kiện xác định của các hàm số:
A) y=2x(x+1)
B) y=3x/2x-3 (chỗ này là 3x trên 2x-3 chứ ko phải 3.x trên 2x-3 đâu nha)
C) y= 1/x^2-x
D) y=√x^2-4
Mk cần gấp mai nộp rồi thanks mấy bn trc
