A=1/2+1/3+1/4+...+1/2019;B=1/2018 +2/2017+3/2016+...+2017/2+2018/1.Tính A/B
\(A=\frac{2017}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+...+\frac{1}{1+2+...+2017}}\)
Tính A=\((1-\dfrac{1}{1+2}).\left(1-\dfrac{1}{1+2+3}\right).\left(1-\dfrac{1}{1+2+3+4}\right)...\left(1-\dfrac{1}{1+2+3+..,+2017}\right)\)
B=1/2+(1/2)^2+(1/2)^3+...+(1/2)^2017
chứng minh rằng
1/2<1/2*3+1/3*3+....+1/n*3+...+1/2017*3<505/2018 ( với mọi n>1)
cho M=1-1/2+1/3-1/4+...+1/2015-1/2016+1/2017
N= 1/1009+1/1010+....+1/2016+1/2017
tính (M-N)^2017
Tính: A = (1- 1/2)(1-1/3)(1-1/4)...(1-1/2016)(1-1/2017)
S= 2^2010 - 2^2009 - 2^2008 - ... - 2 - 1
so sánh a,b biết: a= 2^2018-3/2^2017-1 và b=2^2017-3/2^2016-1
Tính B=\(\left(1-\dfrac{1}{1+2}\right).\left(1-\dfrac{1}{1+2+3}\right).....\left(1-\dfrac{1}{1+2+3+...+2017}\right)\)