Question

1) Tính:

a) \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)\)

b)\(\left(-\frac{1}{3}+\frac{5}{6}\right).11-7\)

c) \(\frac{3}{11}.\frac{4}{15}+\frac{19}{15}.\frac{-3}{11}\)

Answer 1

a/ \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)\)

= \(\frac{2}{3}-2-3\)

=\(\frac{2}{3}-5\)

=\(\frac{2}{3}-\frac{15}{3}\)

=\(\frac{-13}{3}\)

b/\(\left(-\frac{1}{3}+\frac{5}{6}\right).11-7\)

=\(\frac{-11}{3}+\frac{55}{6}-7\)

=\(\frac{-22}{6}+\frac{55}{6}-7\)

= \(\frac{11}{2}-\frac{14}{2}\)

=\(\frac{-3}{2}\)

c/\(\frac{3}{11}.\frac{4}{15}+\frac{19}{15}.\frac{-3}{11}\)

=\(\frac{4}{55}\)\(-\frac{19}{55}\)

=\(\frac{-3}{11}\)

Answer 2

a) \(\frac{2}{3}-4.\left(\frac{1}{2}+\frac{3}{4}\right)=\frac{2}{3}-4.\left(\frac{2}{4}+\frac{3}{4}\right)\)

\(=\frac{2}{3}-4.\frac{5}{4}=\frac{2}{3}-5=\frac{-13}{3}\)

b) \(\left(-\frac{1}{3}+\frac{5}{6}\right).11-7\)

\(=\frac{3}{6}.11-7=\frac{1}{2}.11-7\)

\(=\frac{11}{2}-7=-\frac{3}{2}\)

c) \(\frac{3}{11}.\frac{4}{15}+\frac{19}{15}.\frac{-3}{11}\)

\(=\frac{3}{11}.\left(\frac{4}{15}-\frac{19}{15}\right)\)

\(=\frac{3}{11}.\left(-1\right)=-\frac{3}{11}\)

Chúc bạn học tốt nhé !

Answer 3

Bn thực hiên phép tính theo quy tắc. mk nhgĩ nx bài này chỉ ccân để ý 1 ít lag đc