1.
a) \(\left(3\frac{1}{2}-2x\right).1\frac{1}{3}=7\frac{1}{3}\)
\(\Rightarrow\left(\frac{7}{2}-2x\right).\frac{4}{3}=\frac{22}{3}\)
\(\Rightarrow\left(\frac{7}{2}-2x\right)=\frac{22}{3}:\frac{4}{3}\)
\(\Rightarrow\frac{7}{2}-2x=\frac{11}{2}\)
\(\Rightarrow2x=\frac{7}{2}-\frac{11}{2}\)
\(\Rightarrow2x=-2\)
\(\Rightarrow x=\left(-2\right):2\)
\(\Rightarrow x=-1\)
Vậy \(x=-1.\)
b) \(\frac{4}{5}+\frac{1}{5}:x=\frac{1}{6}\)
\(\Rightarrow\frac{1}{5}:x=\frac{1}{6}-\frac{4}{5}\)
\(\Rightarrow\frac{1}{5}:x=-\frac{19}{30}\)
\(\Rightarrow x=\frac{1}{5}:\left(-\frac{19}{30}\right)\)
\(\Rightarrow x=-\frac{6}{19}\)
Vậy \(x=-\frac{6}{19}.\)
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