ĐKXĐ: \(x\ne\pm\sqrt{10}\)
Sửa đề: \(A=\left(\dfrac{5x+2}{x^2-10}+\dfrac{5x-2}{x^2+10}\right)\cdot\dfrac{x^4-100}{x^2+4}\)
\(=\dfrac{5x^3+50x+2x^2+20+5x^3-50x-2x^2+20}{\left(x^2-10\right)\left(x^2+10\right)}\cdot\dfrac{x^4-100}{x^2+4}\)
\(=\dfrac{10x^3+40}{x^2+4}\)
Khi x=2016 thì \(A=\dfrac{10\left(2016^3+4\right)}{2016^2+4}=\dfrac{8193540100}{406426}\)