1. Thực hiện phép tính :
a. \(A=\left[6.\left(\dfrac{-1}{3}\right)-3.\left(\dfrac{1}{3}\right)+1\right]:\left(-\dfrac{1}{3}-1\right)\)
\(A=\left[-2-1+1\right]:\left(-\dfrac{4}{3}\right)\)
\(A=-2:\left(-\dfrac{4}{3}\right)\)
Vậy : \(A=\dfrac{8}{3}\)