a) \(x^2-10x+16\)
\(=\left(x^2-2x\right)-\left(8x-16\right)\)
\(=x\left(x-2\right)+8\left(x-2\right)\)
\(=\left(x+8\right)\left(x-2\right)\)
b) \(\left(x+1\right)^4+4\left(x+1\right)^2\)
\(=\left(x+1\right)^2\left[\left(x+1\right)^2+4\right]\)
\(=\left(x+1\right)^2\left(x^2+2x+5\right)\)
c)\(x^2\left(x-1\right)+16\left(1-x\right)\)
\(=x^2\left(x-1\right)-16\left(x-1\right)\)
\(=\left(x^2-16\right)\left(x-1\right)\)
\(=\left(x-1\right)\left(x+4\right)\left(x-4\right)\)
Nhớ tick
ta có:
a) x^2 -10x +16
= x^2 - 2.x.5 + 25 -9
= (x-5)^2 -3^2
= (x-8)(x-2)
b) (x+1)^4 + 4(x+1)^2
= (x+1)^2(x^2 +2x+5)
c) x^2(x-1) +16(1-x)
= x^2(x-1) -16(x-1)
= (x-1)( x-4)(x+4)
