a)
Ta có :
\(\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\)
➩\(T_2=\dfrac{T_1V_2}{V_1}=\dfrac{300.2}{8}\)=75 (K)
Ta lại có:
\(\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\)
➩\(P_2=\dfrac{P_1V_1T_2}{T_1V_2}=\dfrac{1.8.75}{300.2}\)=1 am
a, Theo định luật Bôi-lơ–Ma-ri-ốt ta có:
p1V1=p2V2
Suy ra: p2=p1V1/V2
= (8×1)/2=4(atm)