1:|3x-1|-x=2
|3x-1| =2+x
=> 3x-1=2+x hay 3x-1=-2-x
3x-x=2+1 hay 3x+x=-2+1
2x=3 hay 4x=-1
x=3/2 hay x=-1/4
Vậy x=3/2; x=-1/4
2
a 4\(\sqrt{x}=8\)
=>\(\sqrt{x}=2\\ =>x=4\)
b
\(2\sqrt{x}>3\\ \sqrt{x}>\dfrac{3}{2}\\ x>\dfrac{9}{4}\)
c,\(4\sqrt{x}< 13\\ \sqrt{x}< \dfrac{13}{4}\\ x< \dfrac{1703}{16}\)
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