Giải: Kẻ đường thẳng c // b
Vì c // b => \(\widehat{M}=\widehat{Q_1}=76^o\)
Lại có: \(\widehat{Q_1}+\widehat{Q_2}=\widehat{MQP}\)
\(\Rightarrow\widehat{Q_2}=\widehat{MQP}-\widehat{Q_1}=122^o-76^o=46^o\)
Có: c // b mà a // b (gt)
=> c // a
=> \(\widehat{Q_2}=\widehat{P}=46^o\)
Vậy...........
Giải:
Qua Q dựng Qd\(//\)a
c\(//\)b\(\Rightarrow\)\(\widehat{M}=\widehat{Q_1}=76^0\)( Sole trong )
Ta có:\(\widehat{Q_1}+\widehat{Q_2}=122^0\)
\(\Rightarrow\widehat{Q_2}=122^0-\widehat{Q_1}\)
Thay số: \(\widehat{Q_1}=122^0-76^0=46^0\)
Ta lại có:\(\widehat{P}=\widehat{Q_2}=46^0\)( Sole trong )
\(\Rightarrow\widehat{P}=46^0\)
Vậy \(\widehat{P}=46^0\)

