CH3COOH + NaOH => CH3COONa + H2O
mNaOH = 60x10/100 = 6(g)
==> nNaOH = m/M = 0.15 (mol)
Theo pt => nCH3COOH = 0.15 (mol)
mCH3COOH = n.M = 0.15x60 = 9 (g)
C% = 9x100/500 = 1.8%
2CH3COOH + Na2CO3 => 2CH3COONa + CO2 + H2O
nNa2CO3 = 0.1 (mol) > 0.15/2
VCO2 = 22.4n = 22.4 x 0.075 = 1.68 (l)