Bài 1:
PT: \(4Na+O_2\underrightarrow{t^o}2Na_2O\)
\(Ca+\dfrac{1}{2}O_2\underrightarrow{t^o}CaO\)
\(3Fe+2O_2\underrightarrow{t^o}Fe_3O_4\)
\(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
\(S+O_2\underrightarrow{t^o}SO_2\)
\(4P+5O_2\underrightarrow{t^o}2P_2O_5\)
\(C+O_2\underrightarrow{t^o}CO_2\)
\(C_2H_6+\dfrac{7}{2}O_2\underrightarrow{t^o}2CO_2+3H_2O\)
\(C_6H_6+\dfrac{15}{2}O_2\underrightarrow{t^o}6CO_2+3H_2O\)
Bài 2:
Ta có: \(n_P=\dfrac{6,2}{31}=0,2\left(mol\right)\)
PT: \(4P+5O_2\underrightarrow{t^o}2P_2O_5\)
Theo PT: \(n_{P_2O_5}=\dfrac{1}{2}n_P=0,1\left(mol\right)\) \(\Rightarrow m_{P_2O_5}=0,1.142=14,2\left(g\right)\)
Bài 3:
Ta có: \(n_{C_2H_2}=\dfrac{2,6}{26}=0,1\left(mol\right)\)
PT: \(2C_2H_2+5O_2\underrightarrow{t^o}4CO_2+2H_2O\)
Theo PT: \(n_{O_2}=\dfrac{5}{2}n_{C_2H_2}=0,25\left(mol\right)\)
\(\Rightarrow V_{O_2}=0,25.24,79=6,1975\left(l\right)\)
