Question

Answer 1

Câu 23: \(n_{Fe_2O_3}=\dfrac{24}{160}=0,15\left(mol\right)\)

PTHH: \(2Fe\left(OH\right)_3\xrightarrow[]{t^o}Fe_2O_3+3H_2O\)

              0,3<-----------0,15

`=>` \(x=m_{Fe\left(OH\right)_3}=0,3.107=32,1\left(g\right)\)

Câu 17: \(n_{KOH}=0,1.1=0,1\left(mol\right)\)

PTHH: KOH + HCl ---> KCl + H₂O

            0,1---->0,1

`=>` \(C_{M\left(HCl\right)}=\dfrac{0,1}{0,1}=1M\)