`x-2=\sqrt{x-2+2\sqrt{x-3}}` `ĐK: x >= 4`
`<=>x-2=\sqrt{x-3+2\sqrt{x-3}+1}`
`<=>x-2=\sqrt{(\sqrt{x-3}+1)^2}`
`<=>|\sqrt{x-3}+1|=x-2`
`<=>[(\sqrt{x-3}+1=x-2),(\sqrt{x-3}+1=2-x):}`
`<=>[(\sqrt{x-3}=x-3),(\sqrt{x-3}=1-x (VN\text{ vì }x >= 3)):}`
`<=>x-3=x^2-6x+9`
`<=>[(x=3),(x=4):}` (t/m)
Vậy `S={3;4}`

