Question

Answer 1

\(b,=\dfrac{4\left(\sqrt{3}+\sqrt{7}\right)}{3-7}+\dfrac{\sqrt{3}+\sqrt{2}}{3-2}\\ =-\sqrt{3}-\sqrt{7}+\sqrt{3}+\sqrt{2}=\sqrt{2}-\sqrt{7}\)

Answer 2

\(=\dfrac{4\left(\sqrt{3}+\sqrt{7}\right)}{-4}+\dfrac{\sqrt{3}+\sqrt{2}}{1}=-\sqrt{3}-\sqrt{7}+\sqrt{3}+\sqrt{2}=-\sqrt{7}+\sqrt{2}\)