\(\dfrac{x+5}{4}=\dfrac{x-3}{5}\)
=> 5x+25=4x-12
5x-4x=-12-25
x= -37
pttđ:
\(\dfrac{5\left(x+5\right)}{20}=\dfrac{4\left(x-3\right)}{20}\)
=> \(5x+25=4x-12\)
<=> 5x + 25 - 4x + 12 = 0
<=> x + 37 = 0
=> x = -37
b) \(\dfrac{x+5}{4}=\dfrac{x-3}{5}\)
\(\Leftrightarrow5\left(x+5\right)=4\left(x-3\right)\)
\(\Leftrightarrow5x+25=4x-12\)
\(\Leftrightarrow x=-37\)

