\(\Leftrightarrow\dfrac{-17}{5}< \dfrac{-17}{x}< \dfrac{-17}{10}\)
=>17/5>17/x>17/10
=>5<x<10
hay \(x\in\left\{6;7;8;9\right\}\)
`17/(-5) < (-17)/x < 17/(-10)`
` = (-17)/5 < (-17)/x < (-17)/10`
Ta có :
`5 < x < 10`
`=> x ∈ {6,7,8,9}`
Hay :
`17/(-5) < (-17)/6 ; (-17)/7; (-17)/8 ; (-17)/9 < 17/(-10)`
