Answer 1

\(M_A=20.2=40\left(g\text{/}mol\right)\)

Áp dụng sơ đồ đường chéo:

\(\dfrac{n_{N_2}}{n_{CO_2}}=\dfrac{V_{N_2}}{V_{CO_2}}=\dfrac{44-40}{40-28}=\dfrac{1}{3}\\ \rightarrow\left\{{}\begin{matrix}n_{N_2}=\dfrac{1}{1+3}.0,15=0,0375\left(mol\right)\\n_{CO_2}=0,15-0,0375=0,1125\left(mol\right)\end{matrix}\right.\\ \rightarrow\left\{{}\begin{matrix}V_{N_2}=0,0375.22,4=0,84\left(l\right)\\V_{CO_2}=0,1125.22,4=2,52\left(l\right)\end{matrix}\right.\)