Question

Answer 1

Câu 30  :

\(a)C_2H_2 + 2AgNO_3 + 2NH_3 \to Ag_2C_2 + 2NH_4NO_3\\ b)n_{C_2H_2} = n_{Ag_2C_2} = \dfrac{48}{240} = 0,2(mol)\\ \%m_{C_2H_2} = \dfrac{0,2.26}{13,6}.100\% = 38,24\%\\ \%m_{C_2H_4} = 100\% -38,24\% = 61,76\%\)

Answer 2

Câu 29  :

\(X: C_nH_{2n+2}\\ n_{CO_2} = \dfrac{11,2}{22,4} = 0,5(mol)\ ; n_{H_2O} = \dfrac{11,25}{18} = 0,625(mol)\\ \Rightarrow n_X = n_{H_2O} - n_{CO_2} = 0,125(mol)\\ \Rightarrow n = \dfrac{0,5}{0,125} = 4\\ X :C_4H_{10}\\ CTCT : CH_3-CH(CH_3)-CH_3(\text{2-metyl propan})\)

Answer 3

Helppppp meee