Câu hỏi của Hữu Tám

\(\overline{M_X}=\dfrac{2a\cdot2+a\cdot44}{2a+a}=16\left(g\text{/}mol\right)\)\(d_{X\text{/}KK}=\dfrac{16}{29}=0.55\)\(\overline{M_Y}=\dfrac{3b\cdot2+2b\cdot64}{3b+2b}=26.8\left(g\text{/}mol\right)\)\(d_{Y\text{/}KK}=\dfrac{26.8}{29}=0.92\)\(\overline{M_Z}=\dfrac{3c\cdot32+3c\cdot28}{3c+3c}=30\left(g\text{/}mol\right)\)\(d_{Z\text{/}KK}=\dfrac{30}{29}=1.03\) Câu trả lời: \(\overline{M_X}=\dfrac{2a\cdot2+a\cdot44}{2a+a}=16\left(g\text{/}mol\right)\)\(d_{X\text{/}KK}=\dfrac{16}{29}=0.55\)\(\overline{M_Y}=\dfrac{3b\cdot2+2b\cdot64}{3b+2b}=26.8\left(g\text{/}mol\right)\)\(d_{Y\text{/}KK}=\dfrac{26.8}{29}=0.92\)\(\overline{M_Z}=\dfrac{3c\cdot32+3c\cdot28}{3c+3c}=30\left(g\text{/}mol\right)\)\(d_{Z\text{/}KK}=\dfrac{30}{29}=1.03\)