a: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\left(3+\dfrac{3}{8}\right)=\dfrac{27}{8}\cdot\dfrac{12}{7}=\dfrac{81}{14}\)
c: \(=\left(\dfrac{10}{3}+\dfrac{10}{4}\right):\left(\dfrac{19}{6}-\dfrac{21}{5}\right)-\dfrac{11}{31}\)
\(=\dfrac{35}{6}\cdot\dfrac{-30}{31}-\dfrac{11}{31}=-6\)
