a, Vì AD là pg nên \(\dfrac{AB}{AC}=\dfrac{BD}{DC}\Rightarrow\dfrac{DC}{AC}=\dfrac{BD}{AB}\)
Theo tc dãy tỉ số bằng nhau
\(\dfrac{DC}{AC}=\dfrac{BD}{AB}=\dfrac{11}{22}=\dfrac{1}{2}\Rightarrow DC=6cm;BD=5cm\)
b, \(S_{ABD}=\dfrac{1}{2}.AH.BD=\dfrac{1}{2}.8.5=20cm^2\)