\(\lim\limits_{x\rightarrow1}\dfrac{f\left(x\right)-25}{x-1}=12\Rightarrow\) chọn \(f\left(x\right)=12\left(x-1\right)+25=12x+13\)
\(\lim\limits_{x\rightarrow1}\dfrac{\sqrt[3]{12x+15}-3}{x^2-3x+2}=\lim\limits_{x\rightarrow1}\dfrac{12\left(x-1\right)}{\left(x-1\right)\left(x-2\right)\left(\sqrt[3]{\left(12x+15\right)^2}+3\sqrt[3]{12x+15}+9\right)}\)
\(=\lim\limits_{x\rightarrow1}\dfrac{12}{\left(x-2\right)\left(\sqrt[3]{\left(12x+15\right)^2}+3\sqrt[3]{12x+15}+9\right)}=-\dfrac{4}{9}\)
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