Question

Answer 1

1: \(=2018\cdot2^2\cdot\left(-\dfrac{1}{2}\right)^2=2018\)

2: \(=\dfrac{-3}{4}\cdot3^2\cdot\left(-2\right)^2\cdot\dfrac{-1}{3}=\dfrac{-3}{4}\cdot9\cdot4\cdot\dfrac{-1}{3}=9\)

3: \(=\dfrac{2}{5}x^3y^3z^3=\dfrac{2}{5}\cdot1^3\cdot\left(-\dfrac{1}{2}\right)^3\cdot\left(-2\right)^3=\dfrac{2}{5}\)