Câu 1:
a: \(3-4x=-5\)
=>4x=3-(-5)=8
=>x=2
b: \(1+\dfrac{2x+1}{3}< =\dfrac{x-1}{6}-2\)
=>6+2(2x+1)<=x-1-12
=>6+4x+2<=x-13
=>4x+8<=x-13
=>3x<=-21
hay x<=-7
c: \(\Leftrightarrow\dfrac{2}{x+1}+\dfrac{1}{x-2}=\dfrac{3x-11}{\left(x+1\right)\left(x-2\right)}\)
\(\Leftrightarrow2x-4+x+1=3x-11\)
=>-3=-11(vô lý)
d: \(\Leftrightarrow\left|x-3\right|=2x-8\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-8\right)^2=\left(x-3\right)^2\\x>=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2x-8-x+3\right)\left(2x-8+x-3\right)=0\\x>=4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x-5\right)\left(3x-11\right)=0\\x>=4\end{matrix}\right.\Leftrightarrow x=5\)
