Question

Answer 1

\(x^3+6x^2-16x=0\\ \Leftrightarrow x\left(x^2+6x-16\right)=0\\ \Leftrightarrow x\left(x^2-2x+8x-16\right)=0\\ \Leftrightarrow x\left[x\left(x-2\right)+8\left(x-2\right)\right]=0\\ \Leftrightarrow x\left(x-2\right)\left(x+8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\\x+8=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\\x=-8\end{matrix}\right.\)