\(\left\{{}\begin{matrix}\dfrac{2x+3y}{4}-\dfrac{4x-y}{3}=\dfrac{35}{4}\\\dfrac{3x-5y}{3}+\dfrac{2x+7y}{5}=\dfrac{-104}{5}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}\left(\dfrac{2x}{4}-\dfrac{4x}{3}\right)+\left(\dfrac{3y}{4}+\dfrac{y}{3}\right)=\dfrac{35}{4}\\\left(\dfrac{3x}{3}+\dfrac{2x}{5}\right)+\left(\dfrac{-5y}{3}+\dfrac{7y}{5}\right)=\dfrac{-104}{5}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}-\dfrac{5}{6}x+\dfrac{13}{12}y=\dfrac{35}{4}\\\dfrac{7}{5}x+\left(\dfrac{-4}{15}y\right)=\dfrac{-104}{5}\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}-10x+13y=105\\21x-4y=-312\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{-3136}{233}\\y=\dfrac{-915}{233}\end{matrix}\right.\)
