Ta có: \(11\left|x-3\right|-20=3^3-\left(-5\right)^2\)
\(\Leftrightarrow11\left|x-3\right|-20=27-25\)
\(\Leftrightarrow11\left|x-3\right|=22\)
\(\Leftrightarrow\left|x-3\right|=2\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=2\\x-3=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=1\end{matrix}\right.\)
Vậy: \(x\in\left\{5;1\right\}\)

