Bài 8 mình lm rồi nhé
Bài 9:
a) \(=\dfrac{3x-2-7x+4}{2xy}=\dfrac{-4x+2}{2xy}=\dfrac{2\left(-2x+1\right)}{2xy}=-\dfrac{2x-1}{xy}\)
b) \(=\dfrac{3x+2-\left(3x-2\right)+3x-6}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{3x-2}{\left(3x-2\right)\left(3x+2\right)}=\dfrac{1}{3x+2}\)
