Question

Answer 1

Ta có: \(NTK\left(M\right)+14+16.3=85\\ \Rightarrow NTK\left(M\right)=23đvC\\ \Rightarrow M.là:Natri\left(B\right)\)

Answer 2

B

Answer 3

B. Natri

Answer 4

\(PTK_{MNO_3}=NTK_M+NTK_N+3.NTK_O\\ =NTK_M+14+3.16\\ =NTK_M+62\\ Mà:PTK_{MNO_3}=85\left(đ.v.C\right)\\ \Rightarrow NTK_M+62=85\\ \Leftrightarrow NTK_M=23\left(đ.v.C\right)\\ \Rightarrow M:Natri\left(Na=23\right)\\ \Rightarrow Chọn.B\)