Question

Answer 1

giups em vs ạ, em đang cần rất gấp ạ

 

Answer 2

\(a,=\dfrac{\left(x^2+2-2x\right)\left(x^2+2+2x\right)}{yx^2+2y-2xy-x^2+2x-1-1}\)

\(=\dfrac{\left(x^2+2-2x\right)\left(x^2+2+2x\right)}{x^2\left(y-1\right)+2\left(y-1\right)-2x\left(y-1\right)}\)

\(=\dfrac{\left(x^2+2-2x\right)\left(x^2+2+2x\right)}{\left(y-1\right)\left(x^2+2-2x\right)}=\dfrac{x^2+2+2x}{y-1}\)

\(b,=\dfrac{-\left(3n-2\right)\left(m-1\right)}{-\left(m-1\right)^3}=\dfrac{3n-2}{\left(m-1\right)^2}=\dfrac{3n-2}{\left(1-m\right)^2}\)