Question

Answer 1

a, So le trong: \(\widehat{A_3}=\widehat{B_1};\widehat{A_4}=\widehat{B_2}\)

Đồng vị: \(\widehat{A_1}=\widehat{B_1};\widehat{A_2}=\widehat{B_2};\widehat{A_3}=\widehat{B_3};\widehat{A_4}=\widehat{B_4}\)

Trong cùng phía: \(\widehat{A_3}\) và \(\widehat{B_2};\widehat{A_4}\) và \(\widehat{B_1}\)

c, \(\widehat{A_3}=180^0-\widehat{A_2}=60^0\) (kề bù)

Vì a//b nên \(\widehat{A_2}=\widehat{B_2}=120^0\) (đồng vị)

Vậy \(\widehat{B_2}=\widehat{B_4}=120^0\) (đối đỉnh)