\(a,PT\Leftrightarrow x+1=6\Leftrightarrow x=5\\ b,ĐK:x\ge2\\ PT\Leftrightarrow6\sqrt{x-2}-5\sqrt{x-2}=4\\ \Leftrightarrow\sqrt{x-2}=4\\ \Leftrightarrow x-2=16\Leftrightarrow x=18\left(tm\right)\\ c,PT\Leftrightarrow\left|x+2\right|=3\Leftrightarrow\left[{}\begin{matrix}x+2=3\\x+2=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-5\end{matrix}\right.\)
a)x+1=6
x=5
Vậy x=5
b)\(2\sqrt{9\left(x-2\right)}-\dfrac{5}{2}\sqrt{4\left(x-2\right)}=4\)
\(6\sqrt{\left(x-2\right)}-\dfrac{5}{2}\sqrt{\left(x-2\right)}=4\)
\(\dfrac{7}{2}\sqrt{\left(x-2\right)}=4\)
\(\sqrt{x-2}=4-\dfrac{7}{2}\)
\(\sqrt{x-2}=\dfrac{1}{2}\)
\(\sqrt{x-2}=\sqrt{\dfrac{1}{4}}\)
\(x-2=\dfrac{1}{4}\)
\(x=\dfrac{9}{4}\)
Vậy \(x=\dfrac{9}{4}\)
c)\(\sqrt{\left(x+2\right)^2}-2=1\)
\(\left|x+2\right|-2=1\)
\(x+2-2=1\)
\(x=1\)
Vậy x=1
