\(\sqrt{4-2\sqrt{3}}+\sqrt{28-10\sqrt{3}}=\sqrt{\left(2-\sqrt{3}\right)^2}+\sqrt{\left(5-\sqrt{3}\right)^2}\)
=2-\(\sqrt{3}\)+5-\(\sqrt{3}\)=7-2\(\sqrt{3}\)
\(=\sqrt{\left(\sqrt{3}-1\right)^2}+\sqrt{\left(5-\sqrt{3}\right)^2}\\ =\sqrt{3}-1+5-\sqrt{3}=4\)