ĐKXĐ \(x\ge-1\)
\(3x-\sqrt{x+1}+1=0\\ \Rightarrow3x+1=\sqrt{x+1}\\ \Rightarrow9x^2+6x+1=x+1\\ \Rightarrow9x^2+5x=0\\ \Rightarrow x\left(9x+5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{5}{9}\end{matrix}\right.\)
Thử lại \(x=-\dfrac{5}{9}\) không thỏa mãn \(\Rightarrow x=0\)