Question

Answer 1

cần gấp ak 

Answer 2

109⁰

Answer 3

109⁰

Answer 4

Kẻ Bz//Az//Cy

\(\Rightarrow\left\{{}\begin{matrix}\widehat{ABz}=\widehat{A}=45^0\left(so.le.trong\right)\\\widehat{CBz}=180^0-\widehat{C}=180^0-116^0=64^0\left(trong.cùng,phía\right)\end{matrix}\right.\)

\(\Rightarrow\widehat{ABC}=\widehat{ABz}+\widehat{CBz}=45^0+64^0=109^0\)

Answer 5

109⁰