Bài 2:
a: |3-2x|=5
=>|2x-3|=5
=>\(\left[\begin{array}{l}2x-3=5\\ 2x-3=-5\end{array}\right.\Rightarrow\left[\begin{array}{l}2x=8\\ 2x=-2\end{array}\right.\Rightarrow\left[\begin{array}{l}x=4\\ x=-1\end{array}\right.\)
b: \(-\frac{11}{12}\cdot\left(x+0,25\right)=-\frac56\)
=>\(x+\frac14=-\frac56:\frac{-11}{12}=\frac56\cdot\frac{12}{11}=\frac{5\cdot2}{11}=\frac{10}{11}\)
=>\(x=\frac{10}{11}-\frac14=\frac{40-11}{44}=\frac{29}{44}\)
c: \(\left(3-x\right)^5=-32\)
=>3-x=-2
=>x-3=2
=>x=2+3
=>x=5
Bài 1:
a: \(8\frac29:\frac{-3}{8}-5\frac29:\frac{-3}{8}\)
\(=\left(8+\frac29-5-\frac29\right):\frac{-3}{8}\)
\(=3\cdot\frac{-8}{3}=-8\)
b: \(\left(0,25\right)^6\cdot\left(-4\right)^6-\frac{72^2}{36^2}\)
\(=\left(-4\cdot0,25\right)^6-2^2=1-4=-3\)
c: \(-1,25\cdot\left(-4,1\right)\cdot8+0,2=4,1\cdot1,25\cdot8+0,2\)
=41+0,2
=41,2
