\(=\left(\dfrac{3\sqrt{6}}{2}+\dfrac{2\sqrt{6}}{3}-2\sqrt{6}\right)\left(\sqrt{6}-2\sqrt{3}-\sqrt{6}\right)\\ =\dfrac{9\sqrt{6}+4\sqrt{6}-12\sqrt{6}}{6}\left(-2\sqrt{3}\right)\\ =\dfrac{\sqrt{6}\left(-2\sqrt{3}\right)}{6}=\dfrac{-6\sqrt{2}}{6}=-\sqrt{2}\)