\(3,\\ a,\left\{{}\begin{matrix}a//b\\c\perp a\end{matrix}\right.\Rightarrow b\perp c\\ b,\widehat{A_1}=\widehat{A_3}=115^0\left(đối.đỉnh\right)\\ a//b\Rightarrow\widehat{A_1}=\widehat{B_3}=115^0\left(so.le.trong\right)\\ \widehat{B_3}+\widehat{B_2}=180^0\left(kề.bù\right)\\ \Rightarrow\widehat{B_2}=180^0-\widehat{B_3}=180^0-115^0=65^0\)


