Question

Answer 1

\(a,=3\left(\sqrt{3}-1\right)+25\sqrt{2}+2\\ =3\sqrt{3}+25\sqrt{2}-1\\ b,=-15\sqrt{5}+15+126-10\sqrt{5}\\ =141-25\sqrt{5}\\ c,=\sqrt{\left(\sqrt{2}+\sqrt{3}\right)^2}-\sqrt{\left(\sqrt{3}-\sqrt{2}\right)^2}\\ =\sqrt{3}+\sqrt{2}-\sqrt{3}+\sqrt{2}=2\sqrt{2}\\ d,=\sqrt{49-20\sqrt{6}}-\sqrt{49+20\sqrt{6}}\\ =\sqrt{\left(5-2\sqrt{6}\right)^2}-\sqrt{\left(5+2\sqrt{6}\right)^2}\\ =5-2\sqrt{6}-5-2\sqrt{6}=-4\sqrt{6}\)