\(a,=\dfrac{\sqrt{5}\left(\sqrt{5}-2\right)}{\sqrt{5}-2}-\dfrac{8\left(\sqrt{5}+1\right)}{4}+\sqrt{\left(2\sqrt{5}-3\right)^2}\\ =\sqrt{5}-2\left(\sqrt{5}+1\right)+2\sqrt{5}-3=\sqrt{5}-5\)
\(b,=\dfrac{5\left(\sqrt{6}-1\right)}{5}+\dfrac{\sqrt{6}\left(\sqrt{2}-\sqrt{3}\right)}{\left(\sqrt{3}-\sqrt{2}\right)}+4\sqrt{6}\\ =\sqrt{6}-1+\sqrt{6}+4\sqrt{6}=6\sqrt{6}-1\)
\(c,=\dfrac{5\left(\sqrt{3}-\sqrt{2}\right)}{\sqrt{3}-\sqrt{2}}+\dfrac{\sqrt{5}\left(\sqrt{5}-2\right)}{1}+\dfrac{\sqrt{5}\left(\sqrt{5}-1\right)}{\sqrt{5}-1}\\ =5+5-2\sqrt{5}+\sqrt{5}=10-\sqrt{5}\)
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