Question

Answer 1

\(B=\dfrac{x-1-4\sqrt{x}+\sqrt{x}+1}{x-1}.\dfrac{x-1}{x-2\sqrt{x}}\)

\(=\dfrac{x-3\sqrt{x}}{x-2\sqrt{x}}\)

Answer 2

Ace giúp mik phát.Mik cần gấp

Answer 3

\(B=\left(1-\dfrac{4\sqrt{x}}{x-1}+\dfrac{1}{\sqrt{x}-1}\right):\dfrac{x-2\sqrt{x}}{x-1}\left(x>0;x\ne1\right)\\ B=\dfrac{x-1-4\sqrt{x}+\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}-2\right)}\\ B=\dfrac{x-3\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-2\right)}=\dfrac{\sqrt{x}-3}{\sqrt{x}-2}\)