e) \(3x-1-\sqrt{4x^2-12x+9}=0\) ĐK: \(x\ge\dfrac{3}{2}\)
\(\Leftrightarrow3x-1=\sqrt{4x^2-12x+9}\)
\(\Leftrightarrow9x^2-6x+1=4x^2-12x+9\)
\(\Leftrightarrow5x^2+6x-8=0\)
\(\Leftrightarrow\left(5x-4\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{5}\left(tm\right)\\x=-2\left(loại\right)\end{matrix}\right.\)
f giống e




