Bài tập 5:
\(2Na+2H_2O\rightarrow2NaOH+H_2\\ SO_3+H_2O\rightarrow H_2SO_4\\ BaO+H_2O\rightarrow Ba\left(OH\right)_2\\ Zn+2HCl\rightarrow ZnCl_2+H_2\\ 2K+2H_2O\rightarrow2KOH+H_2\\ P_2O_5+3H_2O\rightarrow2H_3PO_4\\ CaO+H_2O\rightarrow Ca\left(OH\right)_2\\ Fe+2HCl\rightarrow FeCl_2+H_2\)
Bài tập 8.1:
\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ 0,4.......1,2..........0,4..........0,6\left(mol\right)\\ a.V_{H_2\left(đktc\right)}=0,6.22,4=13,44\left(l\right)\\ b.m_{HCl}=36,5.1,2=43,8\left(g\right)\)
Bài tập 8.2:
\(n_{Al}=\dfrac{10,8}{27}=0,4\left(mol\right)\\ n_{HCl}=\dfrac{73}{36,5}=2\left(mol\right)\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\\ Vì:\dfrac{0,4}{2}< \dfrac{2}{6}\\ \Rightarrow HCldư\\ n_{HCl\left(dư\right)}=2-\dfrac{6}{2}.0,4=0,8\left(mol\right)\\ m_{HCl\left(dư\right)}=0,8.36,5=29,2\left(g\right)\\ b.n_{H_2}=\dfrac{3}{2}.0,4=0,6\left(mol\right)\\ V_{H_2\left(đktc\right)}=0,6.22,4=13,44\left(l\right)\)
