Question

Answer 1

\(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{4}{5}-x=\dfrac{1}{5}\)

hay \(x=\dfrac{3}{5}\)

Answer 2

f)\(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\Leftrightarrow1-\dfrac{1}{5}-x=\dfrac{1}{5}\Leftrightarrow x=1-\dfrac{1}{5}-\dfrac{1}{5}=\dfrac{3}{5}\)

Answer 3

7/40+(5/8-x)=1/5

      5/8-x=-1/40

x=13/20

Answer 4

\(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)

<=> \(\dfrac{7}{40}+\dfrac{5}{8}-x=\dfrac{1}{5}\)

<=> x = \(\dfrac{7}{40}+\dfrac{5}{8}-\dfrac{1}{5}\)

<=> x = \(\dfrac{3}{5}\)

Answer 5