Theo đề, ta có:
\(\dfrac{31-n}{43-n}=\dfrac{3}{5}\)
\(\Leftrightarrow155-5n=129-3n\)
\(\Leftrightarrow-2n=-26\)
hay n=13
Theo đề bài, ta có:
\(\dfrac{31-n}{43-n}=\dfrac{3}{5}\)
\(\Rightarrow\) 155 - 5n = 129 - 3n
\(\Rightarrow\) -2n = -26
Vậy n = 13
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