Question

Answer 1

Do a // b nên

.)\(\widehat{A_2}=\widehat{B_4}=55^0(so le trong)\)

.)\(\widehat{B_4}+\widehat{B_1}=180^0\)

\(\Leftrightarrow\)\(\widehat{B_1}=180^0-55^0=125^0\)

.)\(\widehat{B_1}=\widehat{B_3}=125^0(đối đỉnh)\)

.)\(\widehat{A_4}=\widehat{A_2}=55^0(đối đỉnh)\)

 

Answer 2

Lời giải:
Do $a\parallel b$ nên $\widehat{B_4}=\widehat{A_2}=55^0$ (hai góc so le trong)

$\widehat{B_1}+\widehat{B_4}=180^0$

$\Rightarrow \widehat{B_1}=180^0-\widehat{B_4}=180^0-55^0=125^0$

$\widehat{B_3}=\widehat{B_1}=125^0$ (hai góc đối đỉnh)

$\widehat{A_4}=\widehat{A_2}=55^0$ (hai góc đối đỉnh)