Question

Answer 1

thanks mn tối mình nộp r

Answer 2

Bài 2: 

a: Ta có: \(A=\dfrac{3}{4}x^3y^2\cdot\left(4x^2y-x+y^5\right)\)

\(=3x^5y^3-\dfrac{3}{4}x^4t^2+\dfrac{3}{4}x^3y^7\)

b: Ta có: \(B=-\dfrac{2}{3}x\left(-x^4y^2-2x^2-10y^2\right)\)

\(=\dfrac{2}{3}x^5y^2+\dfrac{4}{3}x^3+\dfrac{20}{3}xy^2\)

c: Ta có: \(C=10xy\left(-2x^2y^3+\dfrac{3}{8}y^4-\dfrac{2}{5}xy\right)\)

\(=-20x^3y^4+\dfrac{15}{2}xy^5-4x^2y^2\)