Đặt \(\dfrac{x}{-3}=\dfrac{y}{7}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-3k\\y=7k\end{matrix}\right.\)
Ta có: \(x^2-y^2=-360\)
\(\Leftrightarrow9k^2-49k^2=-360\)
\(\Leftrightarrow k^2=9\)
Trường hợp 1: k=3
\(\Leftrightarrow\left\{{}\begin{matrix}x=-3k=-9\\y=7k=21\end{matrix}\right.\)
Trường hợp 2: k=-3
\(\Leftrightarrow\left\{{}\begin{matrix}x=-3k=9\\y=7k=-21\end{matrix}\right.\)