Question

 =

Answer 1

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^6}{2^{11}.3^5}=\frac{3}{2^4}=\frac{3}{16}\)

Answer 2

3/16

 

Answer 3

\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.9^3}{6^5.2^6}=\frac{2.\left(3.3\right)^3}{\left(3.2\right)^5}=\frac{2.3^33^3}{3^5.2^5}=\frac{3^3}{3^2.2^42^{ }}=\frac{27}{144}=\frac{3}{16}\)